Question 1026908
a.  Since b > a > 0, {{{lim(t->infinity, e^(-at)) = 0}}} and {{{lim(t->infinity, e^(-bt)) = 0}}}, and so{{{lim(t->infinity, C(t)) = 0}}}.

b.  {{{dC(t)/dt = K(be^(-bt) - ae^(-at))}}}