Question 1026935
Make the substitution:
{{{ 1 = log(( 10 )) }}}
{{{ log(( 25 )) - log(( 8x )) = log(( 10 ))
{{{ log(( 25*8x )) = log ((10 )) }}}
{{{ 200x = 10 }}}
{{{ x = 1/20 }}}
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check answer:
{{{ log(( 25 )) - log(( 8x )) = 1 }}}
{{{ log(( 25 )) - log(( 8*(1/20) )) = 1 }}}
{{{ log(( 25 )) - log(( .4 )) = 1 }}}
{{{ 1.3979 - .3979 = 1 }}}
{{{ 1 = 1 }}}
OK