Question 1026926
The first term of a geometric progression is 5 and the fifth term is 1280 find the common ratio of the progression.?

Can I be shown step by step please as I need to be explained this in detail as I do not understand. 
<pre>The formula for a specific term in a GP is: {{{a[n] = a[1]r^(n - 1)}}}, where:
{{{a[n]}}} is the value of the term 
{{{a[1]}}} is the value of the 1<sup>st</sup> term
{{{n}}}    is the term number

For the 5<sup>th</sup> term, {{{a[n] = a[1]r^(n - 1)}}} becomes: 
{{{a[5] = 5r^(5 - 1)}}}
{{{matrix(1,3, "1,280", "=", 5r^4)}}}
{{{matrix(1,3, "1,280"/5, "=", r^4)}}}
{{{256 = r^4}}}
{{{r = root (4, 256)}}}
{{{highlight_green(matrix(1,6, r, or, common, ratio, "=", " "+- 4))}}}