Question 1026838
Find the x & y intercept points by plugging x=0,y=0 in both equations.													#DIV/0!
equation I													110.77
when x=	0	y=	-6	,(	0	,	-6	)					0.17
when y =	0	x=	-6	,(	-2	,	0	)					
Equation 2													
when x=	0	y=	1	(	0	,	1	)					
when y =	0	x=	-2	(	-2	,	0	)					
													
{{{drawing(300,300,-10,10,-10,10,circle(0,1,0.3),circle(-2,0,0.3),graph(300,300,-10,10,-10,10,y=-3x-6,y=(1/2)x+1))}}}													
													
You will observe that the point of intersection is						-2	,	0					
The solution of the system is			(  	-2	,	0	)