Question 1026814
csc 3θ = 6 sin 3θ
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(1/sin(3t)) = 6*sin(3t)
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sin^2(3t) = 1/6
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sin(3t) = 1/sqrt(6)
3t = arcsin(1/sqrt(6)) = (0.42+-2npi) radians
t = (0.14 +- (2/3)npi) radians 
(a) Find all solutions of the equation. 
θ = (0.14 +- (2/3)npi) radians 
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(b) Find the solutions in the interval [0, 2π). 
θ = 0.14+-(2/3)pi
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Cheers,
Stan H.