<PRE><B>Question 1026827</B>
Decide whether each pair of lines are parallel, perpendicular, or neither.
(1/3)y+(10/9)x = 1/3
(1/3)y = (-10/9)x + (1/3)
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slope = (-10/9)/(1/3) = -10/3 
y-int = (1/3)/(1/3) = 1 
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and 10y-40=3x
10y = 3x + 40
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slope = 3/10 ; y-int = 4
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Ans: Since (-10/3)(3/10) = -1, the lines are perpendicular
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Cheers,
Stan H.
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