Question 1026796
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Completing the square.

1.)x^2+6x=7

2.) x^2+8x=9

3.) 9x^2+19x=-8 (solve by completing the square an coefficient of x^2 is 1)

I'm looking for the processes of these. The book examples don't help.
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1) {{{x^2+6x}}} = {{{7}}},

   {{{x^2 + 6x - 7}}} = {{{0}}}

   {{{(x^2 - 6x + 9) - 9 - 7}}} = {{{0}}},      ( I added and distracted 9 )

   {{{(x-3)^2 - 16}}} = {{{0}}}              ( {{{(x^2 - 6x + 9)}}} = {{{(x-3)^2}}} )

   {{{(x-3)^2}}} = {{{16}}},                 ( Now take the square root from both sides )

   {{{x-3}}} = +/- 4,

   x = 3 +/- 4,

   x = 7 and/or x = -1.


2)  x^2+8x=9      is exactly the same.  Do it yourself.

3)  9x^2+19x=-8   I suspect you missed something here.
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