Question 1026769
Let the two digits be a & b
then
10a + b = the number
and
c = the same digits mentioned in the 2nd statement
:
Write an equation for each statement
:
If sum of two digit number be 14.
a + b = 14
b = -a + 14; use this form for substitution
:
 when 29 is subtracted from the number then the digit become same.
10a + b - 29 = 10c + c
10a + b = 11c + 29
Replace b with (-a+14)
10a - a + 14 = 11c + 29
9a = 11c + 29 - 14
9a = 11c + 15
a = {{{(11c+15)/9}}}
If we examine this equation we can see there is only one single integer solution
c = 6, then a = 9
therefore
 b = -9 + 14
 b = 5
:
Find the number 95
:
:
See if that checks out in the 2nd statement
 "when 29 is subtracted from the number then the digits become same."
95 - 29 = 66
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