Question 1026521
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ 4(0.95)^x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(-1)\ =\ 4(0.95)^{-1}\ =\ \frac{4}{0.95}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(2)\ =\ 4(0.95)^2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(3)\ =\ 4(0.95)^3]


This is nothing more than calculator work.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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