Question 1026629
 
Question:
Suppose GRE Verbal scores are normally distributed with a mean of 459 and a standard deviation of 120.  A university plans to offer tutoring jobs to students whose scores are in the top 14%.  What is the minimum score required for the job offer? 
 
Solution:
Top 14% means that 86% of the students are below.
The corresponding Z-score can be read from the Normal Distribution table as:
P(Z≤1.0803)=86% (left-tail only).
So convert to number of students,
Z=(X-μ)/σ
means that
X=Z*σ+&mu=1.0803*120+459=588.6
So minimum score is 588.6 to be in the top 14%.