Question 1026553
Assume we have to removae x quarts of antifreeze from the radiator and add 100% one

Antifreeze													
	percent	----------------			quantity								
Antifreeze pure	100.00%	----------------			x	quarts							
Antifreeze I	30.00%	------	10	-	x	quarts							
Mixture	50.00%	----------------	10										
	10												
100.00%	x	+	30.00%	(	10	-	x	)	=	50.00%	*	10	
100	x	+	30	(	10	-	x	)	=	500			
100	x	+	300	-	30	x	=			500			
100	x	-	30	x			=	500	-	-300			
70	x			=	200								
/	70												
	x			=	2.86		quarts			100.00%		Antifreeze pure	
					7.14		quarts			30.00%		Antifreeze I	
													
m.ananth@hotmail.ca