Question 1026537
{{{(8^2)^x=1/(2^4)}}}


{{{((2^3)^2)^x=2^(-4)}}}


{{{(2^6)^x=2^(-4)}}}


{{{2^(6x)=2^(-4)}}}


Bases are the same, so the exponents are equal.


{{{6x=-4}}}


{{{x=-2/3}}}