Question 1026453
The price really doesn't matter, so
I'll just say it is {{{ p }}}
I'll convert the % to equivilant fraction
It was sold for {{{ p - (1/3)*p = (2/3)*p }}}
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Let {{{ k }}} = the fraction to factor by
Now you want:
{{{ k*( 2/3 )*p = p }}}
Divide both sides by {{{ p }}}
{{{ k*( 2/3 ) = 1 }}}
{{{ k = ( 3/2 ) }}}
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So I have:
{{{ (3/2)*(2/3)*p = p }}}
{{{ ( 1 + 1/2 )*( 2/3)*p = p }}}
{{{ ( 2/3)*p + (1/2)*( 2/3)*p = p }}}
So, {{{ (2/3)*p }}} must be increased by {{{ 1/2 }}} or 50%
to get back to {{{ p }}} ( which is $240 in this case )