Question 1026395
Let the numbers be n and n+2

n(n+2) = 5n+6


{{{n^2+2n =5n+6}}}


{{{n^2-3n-6=0}}}


{{{n^2-3n+2n-6=0}}}


n(n-3)+2(n-3)=0

(n-3)(n+2)=0

n=3 or n=-2

odd number so n=3

3,5 are the numbers