<PRE><B>Question 88017</B>
A manufacturer produces both two-slice and four-slice toasters. The two-slice
toaster takes 6 h of labor to produce and the four-slice toaster 10 h. The labor available is limited to 300 h per week, and the total production capacity is 40 toasters per week. Write a system of inequalities representing this situation.
: 
x = no. of 2-slice
y = no. of 4-slice
:
Labor equation:
6x + 10y =&lt; 300
Arrange equation for graphing:
10y =&lt; 300 - 6x
y =&lt; (300/10) - (6/10)x
y =&lt; 30 - .6x; graph this
:
Production equation
x + y =&lt; 40
y =&lt; 40 - x; graph this also
:
Then, draw a graph of the feasible region, given these conditions, in which x is the number of two-slice toasters and y is the number of four-slice toasters.
:
{{{ graph( 300, 200, -10, 50, -10, 50,  30-.6x, 40-x) }}}
:
Feasibility region at or below both lines, which ever is lowest.
obviously only the positive region is considered
:
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