Question 1026040
*[illustration cc8.JPG].
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.
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{{{2sin(2x)sin(x)=2cos(x)}}}
{{{sin(2x)sin(x)=cos(x)}}}
{{{2sin^2(x)cos(x)=cos(x)}}}
{{{2sin^2(x)=1}}}
{{{sin^2(x)=1/2}}}
So,
{{{sin(x)=sqrt(2)/2}}}
and 
{{{sin(x)=-sqrt(2)/2}}}
I leave it to you to solve for x and verify that these are the same solutions as the graph.