Question 1026291
I need help with this problem:
Find the area of the region completely enclosed by the graphs of y = {{{x^2 - 2}}} and y = x.
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Find the 2 points of intersection.
{{{x^2 - 2 = x}}}
{{{x^2 - x - 2 = 0}}}
x = -1 and x = 2
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f(x) = {{{x^2 - x - 2 = 0}}}
F(x) = {{{x^3/3 - x^2/2 - 2x}}}  Ignore the constant of integration.
Area = F(2) - F(-1)
= (8/3 - 2 - 4) - (-1/3 - 1/2 + 2)
= (-10/3) - (7/6)
= -27/6
Area = ABS = 4.5 sq units