Question 1026268
x^2-2x-3>0
x^2-3x+x-3>0
x[x^2/x-3x/x]+(x-3)>0
x(x-3)+(x-3)>0
(x-3)(x+1)>0
x-3=0
x+1=0
x=3
x=3
x=-1
x<-1
-1<x<3
x>3
x^2-3>2x
(-2)^2-3>2(-2)
x<-1
x>3