Question 1026221
Let {{{ t }}} = the time in hours that 
will make you arrive on time
Let {{{ d }}} = your distance in miles 
from the station
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Equation for arriving late:
(1) {{{ d = 80*( t + 1/4 ) }}}
Equation for arriving early:
(2) {{{ d = 110*( t - 1/6 ) }}}
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( note that I converted minutes to 
fractions of an hour )
Substitute (1) into (2)
(2) {{{ 110*( t - 1/6 ) = 80*( t + 1/4 ) }}}
Divide both sides by {{{ 10 }}}
(2) {{{ 11*( t - 1/6 ) = 8*( t + 1/4 ) }}}
(2) {{{ 11t - 11/6 = 8t + 2 }}}
(2) {{{ 3t = 12/6 + 11/6 }}}
(2) {{{ 3t = 23/6 }}}
(2) {{{ t = 23/18 }}}
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Plug this result back into either equation
to get {{{ d }}}
(1) {{{ d = 80*( t + 1/4 ) }}}
(1) {{{ d = 80*( 23/18 + 1/4 ) }}}
(1) {{{ d = 80*( 46/36 + 9/36 ) }}}
(1) {{{ d = 80*( 55/36 ) }}}
(1) {{{ d = 122.222 }}} mi
You live 122.222 mi from station
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check answer:
(2) {{{ d = 110*( t - 1/6 ) }}}
(2) {{{ d = 110*( 23/18 - 3/18 ) }}}
(2) {{{ d = 110*( 10/9 ) }}}
(2) {{{ d = 122.222 }}}
OK
Hope I got it -you might want a 2nd opinion