Question 88314
Just add the two equations together, and the y terms subtract out:

x+y=7
2x-y=5
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3x=12
x=4


Substitute back into the first equation:
x+y=7
4+y=7
y=3


Check by substituting both values in the second equation:

2x-y=5
2*(4)-3=5

It checks.


The solution is the point (4,3).


R^2