Question 88292
{{{3x^2-4x-5=0}}}
Quadratic Formula: 
{{{x=(-b+-sqrt(b^2-4ac))/2a}}}
In this case, a=3, b=-4, c=-5
So, plug and chug:
{{{x=(4+-sqrt((-4)^2-(4*3*(-5))))/(2*3)}}}
Simplify:
{{{x=(4+-sqrt(16+60))/6}}}
{{{x=(4+-sqrt(76))/6}}}
Simplify the radical:
x=(4+-2sqrt(19))/6
Cancel out a 2 from numerator and denominator:
{{{highlight(x=(2+-sqrt(19))/3)}}}
Good Luck,
tutor_paul@yahoo.com