Question 1026054
This is a sequence of terms that are powers of 4


1 = 4^0
4 = 4^1
16 = 4^2
64 = 4^3
and so on...


So the nth term is {{{4^(n-1)}}} where n is an integer and it starts at n = 1. 


So the function is {{{f(n) = 4^(n-1)}}} and we make the restriction on the domain that n is an integer and {{{n >= 1}}} or {{{n > 0}}}