Question 1026024
y=x+1; domain and range are both (-oo,+oo)
y=x^2+1; domain is infinite (-oo,+oo); range is [1,oo), because x^2 is never less than 0.
{{{graph(300,200,-10,10,-10,10,x^2+1)}}}
y=sqrt(x)+1.  If that is how it should be written, the domain of x is [0,oo); the range is [1,oo)
if sqrt(x+1), then domain is [-1,oo), range [0,oo)
{{{graph(300,200,-10,10,-10,10,sqrt(x+1)))}}}