Question 1026028
area of a parallelogram is b * h, where:


b = the length of the base.
h = the length of the height.


since the bases are the same length, we'll use b for the base of each.l


since the height of the first parallelogram is equal to 1/2 * the height of the second parallelogram, we'll use h for the height of the first parallelogram and we'll use 2h for the height of the second parallelogram.


the area of the first parallelogram is equal to b * h.


the area of the second parallelogram is equal to b * 2 * h.


the ratio of the area of the first parallelogram to the area of the second parallelogram is equal to (b * h) / (b * 2 * h)


the b and the h in the numerator and the denominator cancel out and the result is that the ratio of the area of the first parallelogram to the area of the second parallelogram is 1/2.