Question 1026010
x*p(x).  Strictly speaking the probability of not winning is a little less for $10, because there are chances of winning one of the other two.  Rounding error makes it small enough to ignore.
$1,000,000*1 X 10^(-7)=$0.10
$1000*0.000005=$0.60
$10*0.0002=$0.002.
Probability of losing is (1-.0000001-.000005-0.0002), but that is essentially 1. (it is 0.999749).
That is the loss.
The expected value is 0.702-0.999749=-0.2977, or -$-0.30 rounded to nearest cent.