Question 1026007
Since A and B are independent, P(A&B) = P(A)*P(B) = 1/12.
By the General Addition Law, P(AuB) = P(A) + P(B) - P(A&B) = 1/4 + 1/3 - 1/12 = 1/2.

==> P(A&B|AuB) = P((A&B)&(AuB))/P(AuB) = P(A&B)/P(AuB) = {{{(1/12)/(1/2) = 1/6}}}

Note: (A&B)&(AuB) = A&B because A&B is a subset of AuB.