Question 1026004
Equation is of the form *[tex \large (x+8)^2 + (y-3)^2 = r^2] where r is the radius of the circle.


We know that (-8,3) -- (-3,15) is a radius, so to find r (or r^2), we use the distance formula:


*[tex \large r^2 = (-8 - (-3))^2 + (3 - 15)^2 = (-5)^2 + (-12)^2 = 13^2 = 169]


So the equation of the circle is *[tex \large (x+8)^2 + (y-3)^2 = 169].