Question 88258
{{{x^2-10x+24=0}}}
First, get the x^2 and x terms alone on the left side of the equation:
{{{x^2-10x=-24}}}
Divide the coefficient of x (10) by 2 and square the result. Add this to both
sides of the equation in order to maintain the equality:
{{{x^2-10x+25=-24+25}}}
Convert the left side of the equation to "squared" form and simplify the right side.
{{{(x-5)^2=1}}}
Take the square root of both sides:
x-5=+-1
Solve for x - remember you will get 2 answers... lets take the case of the +1 first:
{{{x-5=1}}}
{{{highlight(x=6)}}}
Now, take the case of -1:
{{{x-5=-1}}}
{{{highlight(x=4)}}}
Good Luck,
tutor_paul@yahoo.com