Question 1025771
{{{((4)/(z))-((7)/(z-2))=(1)/(5)}}}

multiply the equation by 5z(z-2)


{{{(20(z-2))-(35z)=z(z-2)}}}


{{{20z-40-35z= z^2-2z}}}


{{{z^2+13z+40=0}}}

(z+8)(z+5)=0

z=-8 or z=-5

solution set (-8,-5)