Question 1025668
If ln a=2, ln b=3, and ln c=5, evaluate the following: 


 (ln c^−2)(ln a/b^−3)^−3 
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(-2*ln(c))[(ln(a)-ln(b^-3)]^-3
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= -2*5*[(2+3ln(b)]^-3
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= -10[2+3*3]^-3
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= -10[11^-3]
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= -10[1/11^3]
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= -10/1331
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= -0.0075
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Cheers,
Stan H.