Question 1025543
Jolene invests her savings in two bank accounts,

one paying 9% simple interest . Amount = x
 one paying 3% and per year. Amount = 2x  She puts twice as much in the lower-yielding account 
 Her annual interest is 2925 dollars. 

2x*3%+x*9% = 2925

multiply by 100

2x+x = 292500
3x=292500
x=97500

Amount invested at 3% interest is 195000
Amount invested at 9% interest is = 97500