Question 1025597
The diagonal across base is 14
height = 3

The diagonal from the top to the base across =3^2+14^2 = sqrt(205)

For a cuboid diagonal = {{{sqrt(l^2+b^2+h^2)}}}


{{{sqrt(205)}}} = {{{sqrt(10^2+3^2+w^2)}}}

205  = 100+9+w^2

205-100-9 = w^2

96=w^2

w= 4sqrt(6)