Question 1025509
The roots are the x-intercepts not the y-intercepts.
.
.
.
Solving for y-intercepts: Set {{{x=0}}} solve for {{{y}}}
{{{y=(1/2)(0)^2-4}}}
{{{y=-4}}}
({{{0}}},{{{-4}}})
.
.
.
Solving for x-intercepts : Set {{{y=0}}} solve for {{{x}}},
{{{0=(1/2)x^2-4}}}
{{{(1/2)x^2=4}}}
{{{x^2=8}}}
{{{x=0 +- sqrt(8)}}}
{{{x=0 +- 2sqrt(2)}}}
({{{2sqrt(2)}}},{{{0}}})
({{{-2sqrt(2)}}},{{{0}}})
.
.
.
*[illustration cc2.JPG].