Question 1025486
The line through ({{{6}}},{{{0}}}) and ({{{0}}},{{{4}}}) is {{{y=-(2/3)x+4}}}
Standard form has integer coefficients (x coefficient is positive).
{{{3y=-2x+12}}}
{{{highlight_green(2x+3y=12)}}}
or
{{{highlight(2x+3y-12=0)}}}