Question 1025476
Same problem, different numbers.
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How many liters of a 65% acid solution must be mixed with 10% acid solution to get 320 liters of a 30% acid solution?
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 s = amount of 65%
 t = amount of 10%
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 s + t = 320 (total solution)
 65s + 10t = 320*30 (total acid)
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 s + t = 320 --> t = 320 - s
 65s + 10t = 320*30 = 9600
 Sub for t
 65s + 10(320-s) = 9600
 75s + 3200 = 9600
 s = 6400/75
 s = 256/3 liters
 t = 704/3 liters