Question 1025443
{{{(A-4)+(B-4)=48}}}
{{{A+B-8=48}}}
{{{A+B=56}}}
and
{{{A*B=20}}}
{{{A=20/B}}}
Substituting,
{{{20/B+B=56}}}
{{{20+B^2=56B}}}
{{{B^2-56B+20=0}}}
{{{(B^2-56B+784)+20=784}}}
{{{(B+28)^2=764}}}
This does not lead to an integer solution for B since 764 is not a perfect square.
Check the problem set up and repost.