Question 1025448
Chebyshev's theorem states that in general for any distribution, 

{{{P(abs(X - mu)<=k*sigma)>=1-1/k^2}}}.

==> {{{P(abs(X - mu)<=3*sigma)>=1-1/3^2 = 1-1/9 = 8/9}}}, or AT LEAST 88.9% are within 3 standard deviations of the mean.

{{{abs(X - 163)<=3*8 = 24}}} ==> {{{-24 <= X - 163 <=24}}}

==> {{{139 <= X <= 187}}}

==> the minimum and maximum heights that are within 3 standard deviations of the&#8203; mean are 139 and 187, respectively.