Question 1025319
Let {{{ s }}} = Ben's speed in mi/hr
{{{ s - 10 }}} = Ashley's speed in mi/hr
Let {{{ d }}} = distance in miles that Ben travels
{{{ 135 - d }}} = distance that Ashley travels
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Ben's equation:
(1) {{{ d = s*1.5 }}}
Ashley's equation:
(2) {{{ 135 - d = ( s - 10 )*1.5 }}}
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Plug (1) into (2)
(2) {{{ 135 - 1.5s = ( s - 10 )*1.5 }}} 
(2) {{{ 135 - 1.5s = 1.5s - 15 }}}
(2) {{{ 3s = 150 }}}
(2) {{{ s = 50 }}}
and
{{{ s - 10 = 40 }}}
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Ashley's speed is 40 mi/hr
Ben's speed is 50 mi/hr
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check:
(1) {{{ d = 50*1.5 }}}
(1) {{{ d = 75 }}} mi
and
(2) {{{ 135 - d = ( 50 - 10 )*1.5 }}}
(2) {{{ 135 - d = 40*1.5 }}}
(2) {{{ 135 - d = 60 }}}
{{{ 75 + 60 = 135 }}}
OK