Question 1025270
{{{A+B=102}}}
,
,
,
{{{B/A=6+11/A}}}
{{{B=6A+11}}}
,
,
,
Substitute,
{{{A+(6A+11)=102}}}
{{{7A=91}}}
{{{A=13}}}
Then,
{{{B=6(13)+11}}}
{{{B=89}}}