Question 1025237
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Solve. If no solution exists, state this.

n+1/n+2=n-3/n+1
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{{{(n+1)/(n+2)}}} = {{{(n-3)/(n+1)}}}.


Multiply both sides by (n+2)*(n+1). You will get

(n+1)*(n+1) = (n-3)*(n+2),   or

{{{n^2 + 2n + 1}}} = {{{n^2 -n -6}}},   or

3n = -7.

n = {{{-7/3}}}.
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