Question 1025215
Note that the event B is a proper subset of the event A, or B⊂A.  This means 
P(A∩B) = P(B).

Now P(B) = {{{C(5,2)/C(9,2) = 5/18}}}.  Also, 

P(A) = {{{(C(5,2)+C(4,2))/C(9,2) = 4/9}}}

==> P(B|A) = P(A∩B)/P(A) = P(B)/P(A) = {{{(5/18)/(4/9) = highlight(5/8)}}}.

Also,
P(A|B) =  P(A∩B)/P(B) = P(B)/P(B) = {{{highlight(1)}}}.