Question 12594
i am assuming that g(x) = {{{(x+1)/(x-3)}}}?


well, gf(x) would then be {{{(x^2-7x+4)/(x^2-7x)}}} where th edenominator factorises to x(x-7)


So, the domain of this? The domain is "what are the possible x-values i can put in?". Well seeing as how you have given no domain definition for either f(x) or g(x), i will assume that any real value goes, so...


look at the denominator here. What values of x make the fraction go do-lally? The thing you are looking for is any value of x such that the denominator is ZERO, since anything/zero will give an error.


well, we have x(x-7), so either x=0 or x=7 will make the denominator zero, so these 2 values are NOT allowed.


So, domain is xeR, but not 0 or 7.


Need to clarify with your teacher too, if the x=3 from the x-3 of g(x) will be carried over to the composite gf(x) function.


jon.