Question 1025085
A student went online and asked help for solving the equation {{{x(9-x)=14}}}.
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{{{9x-x^2=14}}}
{{{x^2-9x+14=0}}}
{{{x^2-9x+(9/2)^2+14=(9/2)^2}}}
{{{(x-9/2)^2=81/4-56/4}}}
{{{(x-9/2)^2= 25/4}}}
Vertex is ({{{9/2}}},{{{25/4}}}).
The axis of symmetry is {{{x=9/2}}}.
It's a minimum since the quadratic coefficient {{{1>0}}}.
Completing the square,
{{{x-9/2=0 +- (5/2)}}}
{{{x=9/2 +- (5/2)}}}
{{{x=14/2=7}}} and {{{x=4/2=2}}}
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You can also solve with the quadratic equation using {{{a=1}}},{{{b=-9}}},{{{c=14}}}
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
I'll leave that for you. 
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*[illustration pp3.JPG].