Question 88188
If you want to find the vector from the point (-1,2) to (4,6), simply subtract the vector *[Tex \LARGE \v{b}<-1,2>] from  *[Tex \LARGE \v{a}<4,6>] like this. 


*[Tex \LARGE <4,6>-<-1,2>=<4-(-1),6-2>=<5,4>]


So the position vector is 

*[Tex \LARGE <5,4>]



Notice how when we subtract vectors, the resulting vector is a vector from the tip of the first vector to the tip of the second one. To prove that *[Tex \LARGE <5,4>] is the position vector, simply shift the resulting vector to have an initial point at (0,0) (the shifted vector is shown in green). Here you can see that the shifted vector has a terminal point at (5,4). This verifies our answer


{{{drawing(800, 800, -5+2, 5+2, -5+2, 5+2,
graph(800, 800, -5+2, 5+2, -5+2, 5+2, 0),
locate(2,3,Vector A),
locate(-0.5,1,Vector B),
locate(4,6,Position Vector),
locate(3.2,4.2,Position Vector With Initial Point At Origin),
blue(arrow(0,0,4,6)),
red(arrow(0,0,-1,2)),
red(arrow(-1,2,4,6)),
green(arrow(0,0,4--1,6-2))

)}}} Plot of *[Tex \LARGE \v{a}<-1,2>], *[Tex \LARGE \v{b}<4,6>], and the resulting vector *[Tex \LARGE <5,4>]. Notice how the shifted vector is equivalent to the position vector.