Question 1024830
{{{y=(4ln(x+3))/x^2}}}

==> y' = {{{(x^2*4*(1/(x+3)) - 4*ln(x+3)*2x)/x^4}}}, by direct application of the quotient rule.

==> y' = {{{((4x^2)/(x+3) - 8xln(x+3))/x^4}}}

==> y' = {{{((4x)/(x+3) - 8ln(x+3))/x^3}}}

==> y' = {{{(4x - 8(x+3)ln(x+3))/(x^3(x+3))}}}