<PRE><B>Question 88168</B>
(1/3)x + (2/1)y = (3/1)
(2/3)x - (3/5)y = (2/5)
Multiply the 1st equation by 2 to get:
(2/3)x + (4/1)y = (6/1)
Subtract the 2nd equation from that to solve for y, as follows:
(23/5)y = 28/5
y = 28/23
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Substitute into one of the original equations to solve for x, as follows:
(1/3)x + 56/23= 3
(1/3)x = 69/23-56/23
(1/3)x = 13/23
x = 39/23
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Cheers,
Stan H.


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