Question 1024834
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This is a nesting fraction.  I tried the question on two different sites
when my main site, which has taught me a lot, 
didn't make sense.  The question is or problem is 2+2/x (numerator) 4-4/x (denominator)  What is the correct answer please. 
(Its suppose to be reduced as much as possible for the answer.)
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{{{(2 + 2/x)/(4-4/x)}}} = {{{(((2x+2)/x))/(((4x-4)/x))}}} = {{{(2x+2)/(4x-4)}}} = {{{(x+1)/(2*(x-1))}}}.


1.  First I wrote the expression {{{2 + 2/x}}} in the numerator with common denominator:  {{{2 + 2/x}}} = {{{(2x + 2)/x}}}.


2.  Second, I did the same for the expression in the denominator:  {{{4 - 4/x}}} = {{{(4x - 4)/x}}}.

3.  Then I have  {{{(2 + 2/x)/(4-4/x)}}} = {{{(2x+2)/x}}} : {{{(4x-4)/x)}}}. 

    This quotient is the same as the product  {{{(2x+2)/x}}} * {{{x/(4x-4)}}}   ( the rule of dividing ratios ).

    So, the quotient is  {{{(2x+2)/(4x-4)}}}.


4.  As a last step, I cancel the common factor 2 in the numerator and the denominator in this ratio.


5.  Then I got this:  {{{(x+1)/(2*(x-1))}}}.
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