Question 1024810
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{-3\ -\ 3i}{3\ -\ 2i}]


Multiply by 1


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{-3\ -\ 3i}{3\ -\ 2i}\right)\left(\frac{3\ +\ 2i}{3\ +\ 2i}\right)]


The product of a pair of conjugates is the difference of two squares.  Use FOIL to find the product of the numerator binomials.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{-3\ -\ 15i}{13}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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