Question 1024759
 (2/3 p to the power of 4 y cubic) ( y to the power of 4 s to the power of 5) ( 6 p squared s cube) 
:
{{{((2/3)p^4y^3)(y^4s^5)(6p^2s^3)}}}
we don't need the brackets
{{{(2/3)p^4y^3y^4s^5*6p^2s^3}}}
group like terms
{{{(2/3)p^4*6p^2*y^3*y^4*s^5*s^3}}}
2/3 of 6 is 4, add the exponents of like terms so we have
{{{4p^6*y^7*s^8}}}