Question 1024742
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If *[tex \Large l\ =\ 2w\ +\ 10]


Then *[tex \Large A(w)\ =\ 2w^2\ +\ 10w]


But you are given that the area is 28 *[tex \Large m^2], so


*[tex \LARGE \ \ \ \ \ \ \ \ \ 2w^2\ +\ 10w\ -\ 28\ =\ 0]


Solve the factorable quadratic for the positive root.  Once you know *[tex \Large w] you can calculate *[tex \Large 2w\ +\ 10].


The diagonal of a rectangle is the hypotenuse of a right triangle where the sides of the rectangle are the legs of the triangle.  Since you now know the measures of the sides of the rectangle, you can use Pythagoras to calculate the measure of the diagonal.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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